prepbook
  • Introduction
  • Some common stuff
    • python __repr__
    • HackerRank input tips
  • Data Structures and Algorithms
    • Breadth first search
    • Depth First Search
    • Dijkstra
    • A* Search Algorithm
    • Binary Search
    • python counter
    • Sorting
      • Merge Sort
      • Quick Sort
    • Priority Queue
  • Multiprocessing vs Threading
  • Common Coding
    • Find loop in lin list
    • Maximum sum subarray
  • Coding
    • Valid palindrome
    • Palindrome number
    • Remove duplicates from sorted array
    • Island perimeter
    • Serialize and Deserialize Binary Tree
    • Valid Soduku
    • Word Pattern
    • Word Pattern II
    • Group Anagrams
    • Implement Trie
    • Deep copy list with random node
    • Palindrome Permutation
    • Combination Sum
    • Clone Graph
    • Generate parenthesis
    • Fibonacci Number
    • LRU Cache
    • Merge two sorted arrays in place
    • Hamming Distance
    • Merge K sorted arrays
    • Kth smalles element in BST
    • Kth largest element in an array
    • Remove duplicates from sorted list
    • Power of 2
    • Nested list weight sum
    • SIngle number in a list
    • Factor combinations
    • Delete node from BST
  • hacker Rank
    • Coding
      • print staircase
      • Drawing book
      • Challenge 0
      • Min-Max sum
  • WorkRelatedCoding
    • Rectangle Overlap
  • Python tips
Powered by GitBook
On this page

Was this helpful?

  1. Coding

Group Anagrams

Given an array of strings, group anagrams together.

For example, given:["eat", "tea", "tan", "ate", "nat", "bat"], Return:

[
  ["ate", "eat","tea"],
  ["nat","tan"],
  ["bat"]
]

Note:All inputs will be in lower-case.

class Solution(object):
    def groupAnagrams(self, strs):
        """
        :type strs: List[str]
        :rtype: List[List[str]]
        """

        if not strs:
            return []

        #groupedList = []
        dict = {}
        for elem in strs:
            # sort complexity = m log m, where m is the longest string in strs
            x = ''.join(sorted(elem))
            #print 'sorted elem: ', x

            if x not in dict:
                dict[x] = [elem]
            else:
                dict[x] += [elem]

        return dict.values()

        # Total complexity = n * m log m


        '''
        for k,v in dict.iteritems():
            groupedList += [v]

        return groupedList
        '''
PreviousWord Pattern IINextImplement Trie

Last updated 5 years ago

Was this helpful?