prepbook
  • Introduction
  • Some common stuff
    • python __repr__
    • HackerRank input tips
  • Data Structures and Algorithms
    • Breadth first search
    • Depth First Search
    • Dijkstra
    • A* Search Algorithm
    • Binary Search
    • python counter
    • Sorting
      • Merge Sort
      • Quick Sort
    • Priority Queue
  • Multiprocessing vs Threading
  • Common Coding
    • Find loop in lin list
    • Maximum sum subarray
  • Coding
    • Valid palindrome
    • Palindrome number
    • Remove duplicates from sorted array
    • Island perimeter
    • Serialize and Deserialize Binary Tree
    • Valid Soduku
    • Word Pattern
    • Word Pattern II
    • Group Anagrams
    • Implement Trie
    • Deep copy list with random node
    • Palindrome Permutation
    • Combination Sum
    • Clone Graph
    • Generate parenthesis
    • Fibonacci Number
    • LRU Cache
    • Merge two sorted arrays in place
    • Hamming Distance
    • Merge K sorted arrays
    • Kth smalles element in BST
    • Kth largest element in an array
    • Remove duplicates from sorted list
    • Power of 2
    • Nested list weight sum
    • SIngle number in a list
    • Factor combinations
    • Delete node from BST
  • hacker Rank
    • Coding
      • print staircase
      • Drawing book
      • Challenge 0
      • Min-Max sum
  • WorkRelatedCoding
    • Rectangle Overlap
  • Python tips
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  1. Coding

Remove duplicates from sorted array

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example, Given input array nums = [1,1,2],

Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn't matter what you leave beyond the new length.

class Solution(object):
    def removeDuplicates(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        if not nums:
            return 0
        if len(nums) == 1:
            return 1

        idx = 1
        prev = nums[0]
        for elem in nums[1:]:
            if elem != prev:
                nums[idx] = elem     # in place copying of unique elems on duplicate items
                idx += 1
                prev = elem

        return idx

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